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+```mysql
+#按员工工资进行排序，查询当前员工与前一位和后一位的工资平均值
+SELECT *,avg(salary) over (ORDER BY salary rows BETWEEN 1 preceding AND 1 following)  FROM employee;
+
+#查询各部门中小于等于当前员工实际薪资的比例
+SELECT ename,dname,salary,CUME_DIST() over (PARTITION by dname ORDER BY salary DESC) FROM employee;
+
+#查询每个员工工资在全部员工中的排名比例
+SELECT ename,dname,salary,CUME_DIST() over ( ORDER BY salary DESC) FROM employee;
+
+#将所有员工按照工龄分为4个组，并统计每个组的人数
+SELECT ename,hiredate,NTILE(4) over (ORDER BY TIMESTAMPDIFF( YEAR, hiredate, NOW())) FROM employee;
+
+#将员工按照工资分为3个组，并统计组别，每组平均工资，工资范围（first_value、last_value）
+WITH a AS(
+SELECT NTILE(3) over (ORDER BY salary) n,salary FROM employee )
+SELECT n,avg(a.salary),max(salary),min(salary) FROM a GROUP BY a.n;
+
+	#返回员工的实际年龄，如果小于当前日期则减1岁
+SELECT
+	dname,
+	ename,
+	DATEDIFF( NOW(), birth )/365 `DAY` 
+FROM
+	employee 
+ORDER BY
+	birth;
+	
+	#求每个员工还有多少天过生日，并返回下次生日是星期几\
+WITH 
+a as 
+(SELECT 
+ ename,
+ birth,
+ DATEDIFF(DATE_FORMAT(NOW(),'%Y-%m-%d'),CONCAT(YEAR(NOW()),'-',MONTH(birth),'-',DAY(birth))) as `day` FROM employee)
+	SELECT 
+	a.ename,
+	if(a.`day`<0,a.`day`+365,a.`day`) `date`
+	,DATE_FORMAT( CONCAT( YEAR ( NOW() + INTERVAL 1 YEAR ), '-', MONTH ( a.birth ), '-', DAY ( a.birth )), '%W' ) `week` 
+	FROM a;
+	
+```
+