diff --git "a/39 \351\203\255\346\202\246\350\277\216/20230316 \344\275\234\344\270\232.md" "b/39 \351\203\255\346\202\246\350\277\216/20230316 \344\275\234\344\270\232.md" new file mode 100644 index 0000000000000000000000000000000000000000..7311f29fa112b3bdcdf0634905c1c45832dec4ce --- /dev/null +++ "b/39 \351\203\255\346\202\246\350\277\216/20230316 \344\275\234\344\270\232.md" @@ -0,0 +1,62 @@ +```mysql +create database hm3 charset utf8; +use hm3; +create table `user`( +user_id int, +user_name varchar(20), +user_tel int, +ordertime date +); + +create table `order`( +order_id int, +uesr_id int, +type varchar(20), +food varchar(20), +number int, +price int +); + +insert into `user` values +(1,'张三','19865645691','2023-3-13'), +(2,'李四','12345675691','2023-3-13'), +(3,'王五','12895678901','2023-3-13'), +(4,'老六','12345678691','2023-3-14'), +(5,'小七','18945678031',null), +(6,'老八','19345678561','2023-3-16'), +(7,'朱九','15845679911',null); +alter table `user` modify user_tel varchar(20); + +insert into `order` values +(1,1,'快餐','肯德基全家桶',1,50), +(2,1,'快餐','可乐',4,20), +(3,6,'饮料','柠檬水',2,16), +(4,2,'米饭','鱼香肉丝盖饭',5,60), +(5,2,'饮料','珍珠奶茶',3,22), +(6,3,'粉面类','螺蛳粉',4,28), +(7,4,'粉面类','凉拌面',1,10); + +-- 1.在用户表(user)新增一个性别字段user_sex,数据类型为char。 +alter table `user` add user_sex char; +select * from `user`; +-- 2.由于顾客3退单,请把此订单删除。 +delete from `order` where order_id=3; + `order`; +-- 3.老八的电话号码换新了,请将他的号码更新为8888888888。 +update `user` set user_tel='8888888888' where user_name='老八'; +-- 4.查询order表里的最高金额和总金额。 +select max(price),sum(price) from `order`; +-- 5.查询每个顾客分别订购了几个类别。 +select user_name,count(type) from `user` left join (select distinct user_id,type from `order`) a on a.user_id=`user`.user_id group by user_name; +-- 6.查询饮料的总金额 +select sum(price)*sum(number) from `order` where type='饮料'; +-- 7.查询订单表(order)里的订单号,类别(type),食物(food). +select order_id 订单号,type 类别,food 食物 from `order` ; +-- 8.查询没吃饭的人的所有信息 +select `user`.* from `user` left join `order` on `order`.user_id=`user`.user_id where `order`.user_id is null; +-- 9.查询姓老的人的全部信息及订单信息 +select * from `user` left join `order` on `order`.user_id=`user`.user_id where user_name like '老%'; +-- 10.查询总金额大于20的订单里最大值的用户信息,使用降序排列。 +select user_id 用户,sum(price)*sum(number) 总金额 from `order` group by user_id having sum(price)*sum(number)>20 order by sum(price)*sum(number) desc; +``` +