diff --git "a/37 \346\217\255\351\230\263\344\270\275/20220317\345\260\217\347\273\204\344\275\234\344\270\232.txt" "b/37 \346\217\255\351\230\263\344\270\275/20220317\345\260\217\347\273\204\344\275\234\344\270\232.txt"
new file mode 100644
index 0000000000000000000000000000000000000000..ebba002cb7cceae53bd5158c77707f29d8477863
--- /dev/null
+++ "b/37 \346\217\255\351\230\263\344\270\275/20220317\345\260\217\347\273\204\344\275\234\344\270\232.txt"	
@@ -0,0 +1,61 @@
+```mys
+create table user(
+user_id int,
+user_name varchar(20),
+user_tel bigint,
+ordertime date
+);
+
+create table `order`(
+	order_id INT,
+	user_id INT,
+	type VARCHAR ( 20 ),
+	food VARCHAR ( 20 ),
+	number INT,
+	price INT
+);
+
+insert into user values (1,'张三',19865645691,'2023-3-13'); 
+insert into user values (2,'李四',12345675691,'2023-3-13');
+insert into user values (3,'王五',12895678901,'2023-3-13');
+insert into user values (4,'老六',12345678691,'2023-3-14');
+insert into user values (5,'小七',18945678031,null);
+insert into user values (6,'老八',19345678561,'2023-3-16');
+insert into user values (7,'朱九',15845679911,null);
+select * from user;
+
+insert into `order` values (1,1,'快餐','肯德基全家桶',1,50);
+insert into `order` values (2,1,'快餐','可乐',4,20);
+insert into `order` values (3,6,'饮料','柠檬水',2,16);
+insert into `order` values (4,2,'米饭','鱼香肉丝盖饭',5,60);
+insert into `order` values (5,2,'饮料','珍珠奶茶',3,22);
+insert into `order` values (6,3,'粉面类','螺蛳粉',4,28);
+insert into `order` values (7,4,'粉面类','凉拌面',1,10);
+select * from `order`;
+
+
+-- 根据上表所给信息完成下列题目：
+-- 
+
+-- 1.在用户表（user）新增一个性别字段user_sex，数据类型为char。
+alter table user add user_sex char; 
+-- 2.由于顾客3退单，请把此订单删除。
+delete from `order` where order_id=3; 
+-- 3.老八的电话号码换新了，请将他的号码更新为8888888888。
+update user set  user_tel=8888888888 where user_tel=19345678561;
+-- 4.查询order表里的最高金额和总金额。
+select max(price),sum(price) from `order`; 
+-- 5.查询每个顾客分别订购了几个类别。
+select user_name, type from user u left join `order` o on u.user_id=o.uesr_id ;
+-- 6.查询饮料的总金额
+select sum(price) from `order` where type='饮料'; 
+-- 7.查询订单表（order）里的订单号，类别（type），食物（food）.
+select order_id,type,food from `order`; 
+-- 8.查询没吃饭的人的所有信息
+select * from user where user_id not in (select uesr_id from `order`);
+-- 9.查询姓老的人的全部信息及订单信息
+select * from user u left join `order` o on u.user_id=o.uesr_id where user_name like '老%';
+-- 10.查询总金额大于20的订单里最大值的用户信息，使用降序排列。
+select * from user u left join `order` o on u.user_id=o.uesr_id  where price>20  order by price desc;
+```
+