代码拉取完成,页面将自动刷新
def base_check(xnumber, xbase):
for char in xnumber[len(xnumber ) -1]:
if int(char) >= int(xbase):
return False
return True
def convert_from_10(xnumber, xbase, arr, ybase):
if int(xbase) == 2 or int(xbase) == 4 or int(xbase) == 6 or int(xbase) == 8:
if xnumber == 0:
return arr
else:
quotient = int(xnumber) // int(xbase)
remainder = int(xnumber) % int(xbase)
arr.append(remainder)
dividend = quotient
convert_from_10(dividend, xbase, arr, base)
elif int(xbase) == 16:
if int(xnumber) == 0:
return arr
else:
quotient = int(xnumber) // int(xbase)
remainder = int(xnumber) % int(xbase)
if remainder > 9:
if remainder == 10: remainder = 'A'
if remainder == 11: remainder = 'B'
if remainder == 12: remainder = 'C'
if remainder == 13: remainder = 'D'
if remainder == 14: remainder = 'E'
if remainder == 15: remainder = 'F'
arr.append(remainder)
dividend = quotient
convert_from_10(dividend, xbase, arr, ybase)
def convert_to_10(xnumber, xbase, arr, ybase):
if int(xbase) == 10:
for char in xnumber:
arr.append(char)
flipped = arr[::-1]
ans = 0
j = 0
for i in flipped:
ans = ans + (int(i) * (int(ybase) ** j))
j = j + 1
return ans
arrayfrom = []
arrayto = []
is_base_possible = False
number = input("Enter the number you would like to convert: ")
while not is_base_possible:
base = input("What is the base of this number? ")
is_base_possible = base_check(number, base)
if not is_base_possible:
print(f"The number {number} is not a base {base} number")
base = input
else:
break
dBase = input("What is the base you would like to convert to? ")
if int(base) == 10:
convert_from_10(number, dBase, arrayfrom, base)
answer = arrayfrom[::-1] # reverses the array
print(f"In base {dBase} this number is: ")
print(*answer, sep='')
elif int(dBase) == 10:
answer = convert_to_10(number, dBase, arrayto, base)
print(f"In base {dBase} this number is: {answer} ")
else:
number = convert_to_10(number, 10, arrayto, base)
convert_from_10(number, dBase, arrayfrom, base)
answer = arrayfrom[::-1]
print(f"In base {dBase} this number is: ")
print(*answer, sep='')
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