diff --git "a/202122011136 \351\251\254\351\221\253 \347\254\254\344\270\200\346\254\241\344\275\234\344\270\232.ipynb" "b/202122011136 \351\251\254\351\221\253 \347\254\254\344\270\200\346\254\241\344\275\234\344\270\232.ipynb"
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index 0000000000000000000000000000000000000000..f3fe5d1854b8f1f8a095dffbb57addaef128f411
--- /dev/null
+++ "b/202122011136 \351\251\254\351\221\253 \347\254\254\344\270\200\346\254\241\344\275\234\344\270\232.ipynb"	
@@ -0,0 +1,217 @@
+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "id": "5852d813",
+   "metadata": {},
+   "source": [
+    "作业要求以学号命名，类似\"123456.ipynb\"，不需要加姓名。\n",
+    "\n",
+    "\n",
+    "作业提交的方式见下面链接：\n",
+    "https://blog.csdn.net/sheagu/article/details/122397816"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "id": "5d3dca5a",
+   "metadata": {},
+   "source": [
+    "## 题目一\n",
+    "\n",
+    "有一个这样的DNA核酸序列\n",
+    "\n",
+    "“AGCTTTTCATTCTGACTGCAACGGGCAATATGTCTCTGTGTGGATTAAAAAAAGAGTGTCTGATAGCAGC”\n",
+    "\n",
+    "请把这个核酸序列存入一个list，并数一数A、G、C、T各有多少个。"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 20,
+   "id": "e6521351",
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "{'A': 20, 'G': 17, 'C': 12, 'T': 21}\n"
+     ]
+    }
+   ],
+   "source": [
+    "def count_number(str):\n",
+    "    dict = {}\n",
+    "    for i in str:\n",
+    "        if i not in dict:\n",
+    "            dict[i] = 1\n",
+    "        else:\n",
+    "            dict[i] += 1\n",
+    "    return dict\n",
+    "\n",
+    "char = count_number('AGCTTTTCATTCTGACTGCAACGGGCAATATGTCTCTGTGTGGATTAAAAAAAGAGTGTCTGATAGCAGC')\n",
+    "print(char)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "id": "daf8500d",
+   "metadata": {},
+   "source": [
+    "## 题目二\n",
+    "\n",
+    "一个花样滑冰运动员表演后，裁判给表演内容进行评分，分数从0.25分到10分，每次增加值为0.25分。\n",
+    "\n",
+    "试生成一个元组，把可能的得分存入元组，并遍历元组的每一项，打印“一个运动员可能得_____分”。"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 21,
+   "id": "90604ebb",
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "一个运动员可能得0.25分\n",
+      "一个运动员可能得0.5分\n",
+      "一个运动员可能得0.75分\n",
+      "一个运动员可能得1.0分\n",
+      "一个运动员可能得1.25分\n",
+      "一个运动员可能得1.5分\n",
+      "一个运动员可能得1.75分\n",
+      "一个运动员可能得2.0分\n",
+      "一个运动员可能得2.25分\n",
+      "一个运动员可能得2.5分\n",
+      "一个运动员可能得2.75分\n",
+      "一个运动员可能得3.0分\n",
+      "一个运动员可能得3.25分\n",
+      "一个运动员可能得3.5分\n",
+      "一个运动员可能得3.75分\n",
+      "一个运动员可能得4.0分\n",
+      "一个运动员可能得4.25分\n",
+      "一个运动员可能得4.5分\n",
+      "一个运动员可能得4.75分\n",
+      "一个运动员可能得5.0分\n",
+      "一个运动员可能得5.25分\n",
+      "一个运动员可能得5.5分\n",
+      "一个运动员可能得5.75分\n",
+      "一个运动员可能得6.0分\n",
+      "一个运动员可能得6.25分\n",
+      "一个运动员可能得6.5分\n",
+      "一个运动员可能得6.75分\n",
+      "一个运动员可能得7.0分\n",
+      "一个运动员可能得7.25分\n",
+      "一个运动员可能得7.5分\n",
+      "一个运动员可能得7.75分\n",
+      "一个运动员可能得8.0分\n",
+      "一个运动员可能得8.25分\n",
+      "一个运动员可能得8.5分\n",
+      "一个运动员可能得8.75分\n",
+      "一个运动员可能得9.0分\n",
+      "一个运动员可能得9.25分\n",
+      "一个运动员可能得9.5分\n",
+      "一个运动员可能得9.75分\n"
+     ]
+    }
+   ],
+   "source": [
+    "import numpy as np\n",
+    "score = tuple([i for i in np.arange(0.25, 10, 0.25)])\n",
+    "for i in score:\n",
+    "    print(\"一个运动员可能得%s分\"%i)\n",
+    "\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "id": "0c3a4e99",
+   "metadata": {},
+   "source": [
+    "## 题目三\n",
+    "\n",
+    "创建一个字典，列出你所了解的地域美食，比如{'肠粉':{'城市':'广州','原料':'米'}}。当然，你可以做的更丰富一些。\n",
+    "最后遍历你熟悉的美食，打印出，类似如下的句子：“肠粉是广州的一种美食，它的主要原料是米”。"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 12,
+   "id": "b0026af6",
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "肠粉是广州的一种美食，他的主要原料是米\n",
+      "螺狮粉是柳州的一种美食，他的主要原料是米\n",
+      "双皮奶是汕头的一种美食，他的主要原料是奶\n"
+     ]
+    }
+   ],
+   "source": [
+    "food = {'肠粉':{'城市':'广州', '原料':'米'},\n",
+    "         '螺狮粉':{'城市':'柳州', '原料':'米'},\n",
+    "         '双皮奶':{'城市':'汕头', '原料':'奶'}}\n",
+    "\n",
+    "for key, values in food.items():\n",
+    "    print(\"%s是\" % key + values['城市'] + \"的一种美食，他的主要原料是%s\" % values['原料'])\n",
+    "\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "id": "4c3a6bc9",
+   "metadata": {},
+   "outputs": [],
+   "source": []
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "id": "f0034a8a",
+   "metadata": {},
+   "outputs": [],
+   "source": []
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python 3 (ipykernel)",
+   "language": "python",
+   "name": "python3"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 3
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython3",
+   "version": "3.7.0"
+  },
+  "toc": {
+   "base_numbering": 1,
+   "nav_menu": {},
+   "number_sections": false,
+   "sideBar": true,
+   "skip_h1_title": false,
+   "title_cell": "Table of Contents",
+   "title_sidebar": "Contents",
+   "toc_cell": false,
+   "toc_position": {},
+   "toc_section_display": true,
+   "toc_window_display": false
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 5
+}