From e3d4232a9e5610510fc52709fd9c0afa504a1174 Mon Sep 17 00:00:00 2001 From: gracebun Date: Mon, 28 Mar 2022 10:29:46 +0000 Subject: [PATCH] =?UTF-8?q?=E4=BD=9C=E4=B8=9A?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- 202122011073.ipynb | 212 +++++++++++++++++++++++++++++++++++++++++++++ 1 file changed, 212 insertions(+) create mode 100644 202122011073.ipynb diff --git a/202122011073.ipynb b/202122011073.ipynb new file mode 100644 index 0000000..ade597e --- /dev/null +++ b/202122011073.ipynb @@ -0,0 +1,212 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "作业要求以学号命名，类似\"123456.ipynb\"，不需要加姓名。\n", + "\n", + "\n", + "作业提交的方式见下面链接：\n", + "https://blog.csdn.net/sheagu/article/details/122397816" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## 题目一\n", + "\n", + "有一个这样的DNA核酸序列\n", + "\n", + "“AGCTTTTCATTCTGACTGCAACGGGCAATATGTCTCTGTGTGGATTAAAAAAAGAGTGTCTGATAGCAGC”\n", + "\n", + "请把这个核酸序列存入一个list，并数一数A、G、C、T各有多少个。" + ] + }, + { + "cell_type": "code", + "execution_count": 19, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "['A', 'G', 'C', 'T', 'T', 'T', 'T', 'C', 'A', 'T', 'T', 'C', 'T', 'G', 'A', 'C', 'T', 'G', 'C', 'A', 'A', 'C', 'G', 'G', 'G', 'C', 'A', 'A', 'T', 'A', 'T', 'G', 'T', 'C', 'T', 'C', 'T', 'G', 'T', 'G', 'T', 'G', 'G', 'A', 'T', 'T', 'A', 'A', 'A', 'A', 'A', 'A', 'A', 'G', 'A', 'G', 'T', 'G', 'T', 'C', 'T', 'G', 'A', 'T', 'A', 'G', 'C', 'A', 'G', 'C']\n", + "A有20个。\n", + "G有20个。\n", + "C有20个。\n", + "T有20个。\n" + ] + } + ], + "source": [ + "str_hesuan ='AGCTTTTCATTCTGACTGCAACGGGCAATATGTCTCTGTGTGGATTAAAAAAAGAGTGTCTGATAGCAGC'\n", + "hesuan_list= []\n", + "for i in str_hesuan:\n", + " hesuan_list.append(i)\n", + "print(hesuan_list)\n", + "hesuan_A=[i for i in hesuan_list if i =='A' ]\n", + "print('A有'+str(len(hesuan_A))+'个。')\n", + "hesuan_G=[i for i in hesuan_list if i =='G' ]\n", + "print('G有'+str(len(hesuan_A))+'个。')\n", + "hesuan_C=[i for i in hesuan_list if i =='C' ]\n", + "print('C有'+str(len(hesuan_A))+'个。')\n", + "hesuan_T=[i for i in hesuan_list if i =='T' ]\n", + "print('T有'+str(len(hesuan_A))+'个。')" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## 题目二\n", + "\n", + "一个花样滑冰运动员表演后，裁判给表演内容进行评分，分数从0.25分到10分，每次增加值为0.25分。\n", + "\n", + "试生成一个元组，把可能的得分存入元组，并遍历元组的每一项，打印“一个运动员可能得_____分”。" + ] + }, + { + "cell_type": "code", + "execution_count": 37, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "[0.25, 0.5, 0.75, 1.0, 1.25, 1.5, 1.75, 2.0, 2.25, 2.5, 2.75, 3.0, 3.25, 3.5, 3.75, 4.0, 4.25, 4.5, 4.75, 5.0, 5.25, 5.5, 5.75, 6.0, 6.25, 6.5, 6.75, 7.0, 7.25, 7.5, 7.75, 8.0, 8.25, 8.5, 8.75, 9.0, 9.25, 9.5, 9.75, 10.0]\n", + "(0.25, 0.5, 0.75, 1.0, 1.25, 1.5, 1.75, 2.0, 2.25, 2.5, 2.75, 3.0, 3.25, 3.5, 3.75, 4.0, 4.25, 4.5, 4.75, 5.0, 5.25, 5.5, 5.75, 6.0, 6.25, 6.5, 6.75, 7.0, 7.25, 7.5, 7.75, 8.0, 8.25, 8.5, 8.75, 9.0, 9.25, 9.5, 9.75, 10.0)\n", + "一个运动员可能得0.25分\n", + "一个运动员可能得0.5分\n", + "一个运动员可能得0.75分\n", + "一个运动员可能得1.0分\n", + "一个运动员可能得1.25分\n", + "一个运动员可能得1.5分\n", + "一个运动员可能得1.75分\n", + "一个运动员可能得2.0分\n", + "一个运动员可能得2.25分\n", + "一个运动员可能得2.5分\n", + "一个运动员可能得2.75分\n", + "一个运动员可能得3.0分\n", + "一个运动员可能得3.25分\n", + "一个运动员可能得3.5分\n", + "一个运动员可能得3.75分\n", + "一个运动员可能得4.0分\n", + "一个运动员可能得4.25分\n", + "一个运动员可能得4.5分\n", + "一个运动员可能得4.75分\n", + "一个运动员可能得5.0分\n", + "一个运动员可能得5.25分\n", + "一个运动员可能得5.5分\n", + "一个运动员可能得5.75分\n", + "一个运动员可能得6.0分\n", + "一个运动员可能得6.25分\n", + "一个运动员可能得6.5分\n", + "一个运动员可能得6.75分\n", + "一个运动员可能得7.0分\n", + "一个运动员可能得7.25分\n", + "一个运动员可能得7.5分\n", + "一个运动员可能得7.75分\n", + "一个运动员可能得8.0分\n", + "一个运动员可能得8.25分\n", + "一个运动员可能得8.5分\n", + "一个运动员可能得8.75分\n", + "一个运动员可能得9.0分\n", + "一个运动员可能得9.25分\n", + "一个运动员可能得9.5分\n", + "一个运动员可能得9.75分\n", + "一个运动员可能得10.0分\n" + ] + } + ], + "source": [ + "score=[]\n", + "value=0\n", + "for i in range(40):\n", + " value=value+0.25\n", + " score.append(value)\n", + "print(score)\n", + "score_tuple=tuple(score)\n", + "print(score_tuple)\n", + "for s in score_tuple:\n", + " print('一个运动员可能得'+str(s)+'分')\n", + " \n", + "\n" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## 题目三\n", + "\n", + "创建一个字典，列出你所了解的地域美食，比如{'肠粉':{'城市':'广州','原料':'米'}}。当然，你可以做的更丰富一些。\n", + "最后遍历你熟悉的美食，打印出，类似如下的句子：“肠粉是广州的一种美食，它的主要原料是米”。" + ] + }, + { + "cell_type": "code", + "execution_count": 52, + "metadata": { + "scrolled": true + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "\n", + " 肠粉是一种 广州 美食,它的主要原料是米 \n", + "\n", + " 热干面是一种 武汉 美食,它的主要原料是小麦 \n", + "\n", + " 臭豆腐是一种 长沙 美食,它的主要原料是豆子 \n" + ] + } + ], + "source": [ + "foods = {'肠粉':{'城市':'广州','原料':'米'},'热干面':{'城市':'武汉','原料':'小麦'},'臭豆腐':{'城市':'长沙','原料':'豆子'}}\n", + "for foods_name,foods_information in foods.items():\n", + " print(\"\\n %s是一种 %s 美食,它的主要原料是%s \" %(foods_name,foods_information['城市'],foods_information['原料']))\n", + "\n" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 3", + "language": "python", + "name": "python3" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 3 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython3", + "version": "3.7.0" + }, + "toc": { + "base_numbering": 1, + "nav_menu": {}, + "number_sections": false, + "sideBar": true, + "skip_h1_title": false, + "title_cell": "Table of Contents", + "title_sidebar": "Contents", + "toc_cell": false, + "toc_position": {}, + "toc_section_display": true, + "toc_window_display": false + } + }, + "nbformat": 4, + "nbformat_minor": 5 +} -- Gitee