From e5c1ba24b986b44a27c760a68d38639420b20b6d Mon Sep 17 00:00:00 2001 From: fafa <763457886@qq.com> Date: Sun, 3 Apr 2022 03:48:45 +0000 Subject: [PATCH] 202122011069 --- 202122011069.iqynb | 217 +++++++++++++++++++++++++++++++++++++++++++++ 1 file changed, 217 insertions(+) create mode 100644 202122011069.iqynb diff --git a/202122011069.iqynb b/202122011069.iqynb new file mode 100644 index 0000000..21e02d2 --- /dev/null +++ b/202122011069.iqynb @@ -0,0 +1,217 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "id": "5852d813", + "metadata": {}, + "source": [ + "作业要求以学号命名，类似\"123456.ipynb\"，不需要加姓名。\n", + "\n", + "\n", + "作业提交的方式见下面链接：\n", + "https://blog.csdn.net/sheagu/article/details/122397816" + ] + }, + { + "cell_type": "markdown", + "id": "5d3dca5a", + "metadata": {}, + "source": [ + "## 题目一\n", + "\n", + "有一个这样的DNA核酸序列\n", + "\n", + "“AGCTTTTCATTCTGACTGCAACGGGCAATATGTCTCTGTGTGGATTAAAAAAAGAGTGTCTGATAGCAGC”\n", + "\n", + "请把这个核酸序列存入一个list，并数一数A、G、C、T各有多少个。" + ] + }, + { + "cell_type": "code", + "execution_count": 12, + "id": "e6521351", + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "20 17 12 21\n" + ] + } + ], + "source": [ + "string = 'AGCTTTTCATTCTGACTGCAACGGGCAATATGTCTCTGTGTGGATTAAAAAAAGAGTGTCTGATAGCAGC'\n", + "DNA = list(string)\n", + "num_A,num_G,num_C,num_T = 0,0,0,0\n", + "\n", + "for dna in DNA:\n", + " if dna == 'A':\n", + " num_A += 1\n", + " elif dna == 'G':\n", + " num_G += 1\n", + " elif dna == 'C':\n", + " num_C += 1\n", + " else:\n", + " num_T += 1\n", + "print(num_A,num_G,num_C,num_T)" + ] + }, + { + "cell_type": "markdown", + "id": "daf8500d", + "metadata": {}, + "source": [ + "## 题目二\n", + "\n", + "一个花样滑冰运动员表演后，裁判给表演内容进行评分，分数从0.25分到10分，每次增加值为0.25分。\n", + "\n", + "试生成一个元组，把可能的得分存入元组，并遍历元组的每一项，打印“一个运动员可能得_____分”。" + ] + }, + { + "cell_type": "code", + "execution_count": 6, + "id": "90604ebb", + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "一个运动员可能得0.25分。\n", + "一个运动员可能得0.5分。\n", + "一个运动员可能得0.75分。\n", + "一个运动员可能得1.0分。\n", + "一个运动员可能得1.25分。\n", + "一个运动员可能得1.5分。\n", + "一个运动员可能得1.75分。\n", + "一个运动员可能得2.0分。\n", + "一个运动员可能得2.25分。\n", + "一个运动员可能得2.5分。\n", + "一个运动员可能得2.75分。\n", + "一个运动员可能得3.0分。\n", + "一个运动员可能得3.25分。\n", + "一个运动员可能得3.5分。\n", + "一个运动员可能得3.75分。\n", + "一个运动员可能得4.0分。\n", + "一个运动员可能得4.25分。\n", + "一个运动员可能得4.5分。\n", + "一个运动员可能得4.75分。\n", + "一个运动员可能得5.0分。\n", + "一个运动员可能得5.25分。\n", + "一个运动员可能得5.5分。\n", + "一个运动员可能得5.75分。\n", + "一个运动员可能得6.0分。\n", + "一个运动员可能得6.25分。\n", + "一个运动员可能得6.5分。\n", + "一个运动员可能得6.75分。\n", + "一个运动员可能得7.0分。\n", + "一个运动员可能得7.25分。\n", + "一个运动员可能得7.5分。\n", + "一个运动员可能得7.75分。\n", + "一个运动员可能得8.0分。\n", + "一个运动员可能得8.25分。\n", + "一个运动员可能得8.5分。\n", + "一个运动员可能得8.75分。\n", + "一个运动员可能得9.0分。\n", + "一个运动员可能得9.25分。\n", + "一个运动员可能得9.5分。\n", + "一个运动员可能得9.75分。\n", + "一个运动员可能得10.0分。\n" + ] + } + ], + "source": [ + "# 你的代码\n", + "nums = []\n", + "for i in range(1,41):\n", + " num = i/4\n", + " nums.append(num)\n", + "nums = tuple(nums)\n", + "for a in nums: \n", + " print('一个运动员可能得'+str(a)+'分。')" + ] + }, + { + "cell_type": "markdown", + "id": "0c3a4e99", + "metadata": {}, + "source": [ + "## 题目三\n", + "\n", + "创建一个字典，列出你所了解的地域美食，比如{'肠粉':{'城市':'广州','原料':'米'}}。当然，你可以做的更丰富一些。\n", + "最后遍历你熟悉的美食，打印出，类似如下的句子：“肠粉是广州的一种美食，它的主要原料是米”。" + ] + }, + { + "cell_type": "code", + "execution_count": 16, + "id": "b0026af6", + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "肠粉是广州的一种美食，它的主要原料是米。\n", + "热干面是武汉的一种美食，它的主要原料是面。\n", + "鸭血粉丝汤是南京的一种美食，它的主要原料是肉。\n" + ] + } + ], + "source": [ + "# 你的代码\n", + "delicacy = {\n", + " '肠粉':{'城市':'广州','原料':'米'},\n", + " '热干面':{'城市':'武汉','原料':'面'},\n", + " '鸭血粉丝汤':{'城市':'南京','原料':'肉'},\n", + "}\n", + "for name,information in delicacy.items():\n", + " print(f\"{name}是{information['城市']}的一种美食，它的主要原料是{information['原料']}。\")" + ] + }, + { + "cell_type": "code", + "execution_count": null, + "id": "4c3a6bc9", + "metadata": {}, + "outputs": [], + "source": [] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 3", + "language": "python", + "name": "python3" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 3 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython3", + "version": "3.8.8" + }, + "toc": { + "base_numbering": 1, + "nav_menu": {}, + "number_sections": false, + "sideBar": true, + "skip_h1_title": false, + "title_cell": "Table of Contents", + "title_sidebar": "Contents", + "toc_cell": false, + "toc_position": {}, + "toc_section_display": true, + "toc_window_display": false + } + }, + "nbformat": 4, + "nbformat_minor": 5 +} -- Gitee