From c435c899f5e5d4f34a17c1e72660329a5dc99fc0 Mon Sep 17 00:00:00 2001 From: =?UTF-8?q?=E8=94=A1=E7=8E=AE=E9=93=AD?= <2373854303@qq.com> Date: Tue, 22 Oct 2024 18:04:08 +0800 Subject: [PATCH] =?UTF-8?q?=E6=8F=90=E4=BA=A41022=E4=BD=9C=E4=B8=9A?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- ...74\345\220\210\347\273\203\344\271\240.md" | 314 ++++++++++++++++++ 1 file changed, 314 insertions(+) create mode 100644 "\350\224\241\347\216\256\351\223\255/20241022 \347\273\274\345\220\210\347\273\203\344\271\240.md" diff --git "a/\350\224\241\347\216\256\351\223\255/20241022 \347\273\274\345\220\210\347\273\203\344\271\240.md" "b/\350\224\241\347\216\256\351\223\255/20241022 \347\273\274\345\220\210\347\273\203\344\271\240.md" new file mode 100644 index 0000000..7661df8 --- /dev/null +++ "b/\350\224\241\347\216\256\351\223\255/20241022 \347\273\274\345\220\210\347\273\203\344\271\240.md" @@ -0,0 +1,314 @@ +## 综合练习 + +```sql +# 二、综合题 +-- 1. 描述（10分） +-- 针对如下表Author结构创建索引，写出创建索引的SQL语句： +CREATE TABLE Author +( + Id int PRIMARY KEY , + FirstName varchar(45) NOT NULL, + LastName varchar(45) NOT NULL, + UpdatedTime datetime NOT NULL + ) +-- 对FirstName创建唯一索引uniq_idx_firstname，对LastName创建普通索引idx_lastname +# 答题区： +-- ----------------------------------------------------------------- + -- 对FirstName创建唯一索引uniq_idx_firstname + create unique index uniq_idx_firstname on Author(FirstName); + -- 对LastName创建普通索引idx_lastname + create index idx_lastname on Author(LastName); +-- ----------------------------------------------------------------- + +-- 2. 描述（15分） +-- 构造一个触发器trg_AuditLog，在向Employees表中插入一条数据的时候，触发插入相关的数据到AuditLog中。 +-- -- 职员表 +CREATE TABLE Employees +( + Id INT PRIMARY KEY auto_increment, + Name varchar(80) NOT NULL, + Age INT NOT NULL, + Address varchar(50), + SALARY decimal(18,2) +); +-- -- 审计日志表 +CREATE TABLE AuditLog +( + Id int primary key auto_increment, + NAME TEXT NOT NULL, + Salary decimal(18,2) +); +-- 写好触发器后，往Employees插入一条数据: +INSERT INTO Employees (NAME,AGE,ADDRESS,SALARY)VALUES ('Paul', 32, 'California', 20000.00 ); +-- 然后从AuditLog里面使用查询语句: +select NAME,Salary from AuditLog; +-- 会输出： +mysql> select NAME,Salary from AuditLog; ++------+----------+ +| NAME | Salary | ++------+----------+ +| Paul | 20000.00 | ++------+----------+ + +# 答题区： +-- ----------------------------------------------------------------- +-- 构造一个触发器trg_AuditLog，在向Employees表中插入一条数据的时候，触发插入相关的数据到AuditLog中。 +create trigger trg_AuditLog after insert on Employees for each row +insert into AuditLog (`Name`,Salary) values(new.`Name`,new.Salary); +-- ----------------------------------------------------------------- + +-- 3. 描述（10分） +-- 针对Author表创建视图vw_Author，只包含FirstName以及LastName两列，并对这两列重新命名，FirstName为v_FirstName，LastName修改为v_LastName： +-- 先往Author表插入2条测试数据: +insert into Author values (1,'PENELOPE', 'GUINESS', '2006-02-15 12:34:33'), (2,'NICK', 'WAHLBERG', '2006-02-15 12:34:33'); +-- 查询视图：select * from vw_Author; +-- 输出： ++-------------+------------+ +| v_FirstName | v_LastName | ++-------------+------------+ +| PENELOPE | GUINESS | +| NICK | WAHLBERG | ++-------------+------------+ +# 答题区： +-- ----------------------------------------------------------------- +-- 针对Author表创建视图vw_Author，只包含FirstName以及LastName两列，并对这两列重新命名，FirstName为v_FirstName，LastName修改为v_LastName： +create view vw_Author as select FirstName v_FirstName,LastName v_LastName from Author; +-- ----------------------------------------------------------------- + +-- 4. 描述（10分） +-- 使用以下数据，完成相关操作 +-- -- 新建表 +CREATE TABLE user +( + Id int primary key auto_increment, + UserCode varchar(80), + Birthday date NOT NULL, + FirstName varchar(14) NOT NULL, + LastName varchar(16) NOT NULL, + Gender char(1) NOT NULL, + HireDate date NOT NULL +); +# 插入一些数据： +INSERT INTO `user` (UserCode,Birthday,FirstName,LastName,Gender,HireDate) VALUES('10001','1953-09-02','Georgi','Facello','M','1986-06-26'); +INSERT INTO `user` (UserCode,Birthday,FirstName,LastName,Gender,HireDate) VALUES('10002','1964-06-02','Bezalel','Simmel','F','1985-11-21'); +INSERT INTO `user` (UserCode,Birthday,FirstName,LastName,Gender,HireDate) VALUES('10003','1959-12-03','Parto','Bamford','M','1986-08-28'); +INSERT INTO `user` (UserCode,Birthday,FirstName,LastName,Gender,HireDate) VALUES('10004','1954-05-01','Chirstian','Koblick','M','1986-12-01'); +INSERT INTO `user` (UserCode,Birthday,FirstName,LastName,Gender,HireDate) VALUES('10005','1955-01-21','Kyoichi','Maliniak','M','1989-09-12'); +INSERT INTO `user` (UserCode,Birthday,FirstName,LastName,Gender,HireDate) VALUES('10006','1953-04-20','Anneke','Preusig','F','1989-06-02'); +INSERT INTO `user` (UserCode,Birthday,FirstName,LastName,Gender,HireDate) VALUES('10007','1957-05-23','Tzvetan','Zielinski','F','1989-02-10'); +INSERT INTO `user` (UserCode,Birthday,FirstName,LastName,Gender,HireDate) VALUES('10008','1958-02-19','Saniya','Kalloufi','M','1994-09-15'); +INSERT INTO `user` (UserCode,Birthday,FirstName,LastName,Gender,HireDate) VALUES('10009','1952-04-19','Sumant','Peac','F','1985-02-18'); +INSERT INTO `user` (UserCode,Birthday,FirstName,LastName,Gender,HireDate) VALUES('10010','1963-06-01','Duangkaew','Piveteau','F','1989-08-24'); +INSERT INTO `user` (UserCode,Birthday,FirstName,LastName,Gender,HireDate) VALUES('10011','1953-11-07','Mary','Sluis','F','1990-01-22'); +-- +-- 查询user表，实现以下显示效果： ++----------+------------+-----------+-----------+--------+------------+ +| UserCode | Birthday | FirstName | LastName | Gender | HireDate | ++----------+------------+-----------+-----------+--------+------------+ +| 10001 | 1953-09-02 | Georgi | Facello | 女 | 1986-06-26 | +| 10002 | 1964-06-02 | Bezalel | Simmel | 男 | 1985-11-21 | +| 10003 | 1959-12-03 | Parto | Bamford | 女 | 1986-08-28 | +| 10004 | 1954-05-01 | Chirstian | Koblick | 女 | 1986-12-01 | +| 10005 | 1955-01-21 | Kyoichi | Maliniak | 女 | 1989-09-12 | +| 10006 | 1953-04-20 | Anneke | Preusig | 男 | 1989-06-02 | +| 10007 | 1957-05-23 | Tzvetan | Zielinski | 男 | 1989-02-10 | +| 10008 | 1958-02-19 | Saniya | Kalloufi | 女 | 1994-09-15 | +| 10009 | 1952-04-19 | Sumant | Peac | 男 | 1985-02-18 | +| 10010 | 1963-06-01 | Duangkaew | Piveteau | 男 | 1989-08-24 | +| 10011 | 1953-11-07 | Mary | Sluis | 男 | 1990-01-22 | ++----------+------------+-----------+-----------+--------+------------+ + +# 答题区： +select UserCode, +Birthday, +FirstName, +LastName, +if(Gender!='F','女','男') Gender, +HireDate from `user`; +-- ----------------------------------------------------------------- +-- 5. 描述（30分） +-- 开发组收到M公司的开发邀约，拟开发一套OA办公自动化系统，该系统的部分功能及初步需求分析的结果如下 ： +-- +-- ``` +-- 部门:部门号、部门名、主管、联系电话、邮箱 +-- 员工：工号、姓名、职位、手机号码、薪资 +-- 用户：用户号、用户名、银行账号、手机号码、联系地址 +-- 用户申请：申请号、用户号、会议日期、天数、参会人数、地点、预算和受理标志 +-- ``` +-- +-- （1）M公司旗下有业务部、策划部和其他部门。每个部门只有一名主管，只负责管理本部门的工作，且主管参照员工关系的员工号；一个部门有多名员工，每名员工属于且仅属于一个部门。 +-- +-- （2）员工职位包括主管、业务员、 策划员等。业务员负责受理用户申请，设置受理标志。一名业务员可以受理多个用户申请，但一个用户申请只能由一名业务员受理。 +-- +-- （3）用户号唯一标识用户信息中的每一个用户。 +-- +-- （4）用户申请信息的受理标志有：已申请（默认）、已拒绝、已受理、延期受理、已过期。申请号唯一标识用户申请信息中的每一个申请，且一个用户可以提交多个申请，但一个用户申请只对应一个用户号。 +-- +-- 題目1（10分）：使用PowerDesigner，设计可以使用的数据库物理模型，要求中文名称和英文名称清楚（英文不知道的可以借助翻译软件），表关系准确；利用设计好的模型生成sql语句，创建一个名为OADatabase的数据库，备用； + +-- 题目2（10分）：为了保证当用户申请会议，受理标志为 已申请，请设计一个触发器，当用户申请信息表插入数据的时候，可以判断其默认受理标志是否为：已申请，如果是，则无需处理允许正常插入，如果不是则重新个性受理标志为：已申请； + +# 答题区： +-- ----------------------------------------------------------------- +-- 建库 +drop database if exists OADatabase; + +create database if not exists OADatabase; + +use OADatabase; + +/*==============================================================*/ +/* DBMS name: MySQL 5.0 */ +/* Created on: 2024-10-22 15:17:47 */ +/*==============================================================*/ + + +drop table if exists UserRequest; + +drop table if exists department; + +drop table if exists employee; + +drop table if exists user; + +/*==============================================================*/ +/* Table: UserRequest */ +/*==============================================================*/ +create table UserRequest +( + UserRequest_id int not null auto_increment, + user_number int, + meeting_date date, + day int, + people_counting int, + address varchar(20), + budget decimal(10,2), + Acceptance_mark varchar(10), + primary key (UserRequest_id) +); + +/*==============================================================*/ +/* Table: department */ +/*==============================================================*/ +create table department +( + department_id int not null auto_increment, + department_name varchar(10), + managers varchar(10), + phone varchar(11), + email varchar(11), + primary key (department_id) +); + +/*==============================================================*/ +/* Table: employee */ +/*==============================================================*/ +create table employee +( + employee_id int not null auto_increment, + department_id int not null, + employee_name varchar(10), + job varchar(10), + phone_number varchar(11), + sal decimal(10,2), + primary key (employee_id) +); + +/*==============================================================*/ +/* Table: user */ +/*==============================================================*/ +create table user +( + user_id int not null auto_increment, + employee_id int not null, + UserRequest_id int not null, + user_name varchar(10), + bank_account int, + phone_number varchar(11), + address varchar(20), + primary key (user_id) +); + +alter table employee add constraint FK_link foreign key (department_id) + references department (department_id) on delete restrict on update restrict; + +alter table user add constraint FK_link2 foreign key (employee_id) + references employee (employee_id) on delete restrict on update restrict; + +alter table user add constraint FK_link3 foreign key (UserRequest_id) + references UserRequest (UserRequest_id) on delete restrict on update restrict; +-- 添加数据 +INSERT INTO `department` VALUES (1, '业务部', '肖飞鹏', '10086', '10@qq.com'); +INSERT INTO `department` VALUES (2, '策划部', '叶功照', '10087', '116@qq.com'); +INSERT INTO `department` VALUES (3, '宣传部', '卢比伦', '10088', '119@qq.com'); + +INSERT INTO `employee` VALUES (1, 1, '陈俊杰', '业务员', '100831', 8000.00); +INSERT INTO `employee` VALUES (2, 2, '叶功照', '主管', '10087', 10000.00); +INSERT INTO `employee` VALUES (3, 1, '肖飞鹏', '主管', '10086', 10000.00); +INSERT INTO `employee` VALUES (4, 3, '卢比伦', '主管', '10088', 10000.00); +INSERT INTO `employee` VALUES (5, 1, '刘文辉', '策划员', '1003123', 90000.00); + +INSERT INTO `user` VALUES (1, 5, 1, '王旋', 100200300, '131124121', '闽西职业技术学院'); +INSERT INTO `user` VALUES (2, 5, 2, '曾佳伟', 10220303, '131124021', '闽西职业技术学院'); + +INSERT INTO `userrequest` VALUES (1, 1, '2024-10-22', 7, 10, '望云楼', 2000.00, '已申请'); +INSERT INTO `userrequest` VALUES (2, 2, '2024-10-22', 5, 22, '望云楼', 2000.00, '已申请'); + +-- 答题： +create trigger tri_userrequest before insert on userrequest for each row +begin + if new.Acceptance_mark != '已申请' then + signal sqlstate '66666' set MESSAGE_TEXT = '重新个性受理标志为：已申请；'; + end if; +end; +-- ----------------------------------------------------------------- + +-- 题目3（10分）：当业务员受理用户申请的时候，需要将当前处理的记录中受理标志修改为：已受理，同时将其它所有状态为：已申请，且会议日期已超过的记录中的受理标志个性为：已过期，请设计一个存储过程来处理此业务； + +# 答题区： +-- ----------------------------------------------------------------- +-- 判断存储过程是否存在并删除 +drop procedure if exists pro_accepted; + +-- 修改分割符 +delimiter // + +-- 创建存储过程 +create procedure pro_accepted() +begin + -- 声明变量 + declare now_UserRequest_id int; + declare now_Acceptance_mark varchar(10); + declare now_meeting_date varchar(15); + declare stastu int default 0; + declare now varchar(20) default (select now()); + + -- 声明游标： + declare test cursor for select UserRequest_id,Acceptance_mark,meeting_date from userrequest; + declare continue handler for not found set stastu = 1; + + -- 打开游标： + open test; + + a:loop + fetch test into now_UserRequest_id,now_Acceptance_mark,now_meeting_date; + if stastu = 1 then + leave a; + end if; + if now_Acceptance_mark = '已申请' and now_meeting_date > now then + update userrequest set Acceptance_mark = '已受理' where UserRequest_id = now_UserRequest_id; + else + update userrequest set Acceptance_mark = '已过期' where UserRequest_id = now_UserRequest_id; + end if; + end loop; + +-- 关闭游标： +close test; +end // +-- 还原分隔符 +delimiter ; + +-- 调用存储过程 +call pro_accepted; +-- ----------------------------------------------------------------- +``` -- Gitee