'''
    python 高级笔记 根据值大小对字典进行排序
    来源:https://www.bilibili.com/video/BV1b5411s76z?p=4
'''

from random import randint
import timeit
dict01 = {
    'age07': 2,
    'age05': 3,
    'age05': 4,
    'age04': 5,
    'age02': 1,
}
tuble01 = [(v, k) for (k, v) in dict01.items()]
tuble02 = sorted(tuble01,reverse=True)
tuble03 = sorted(tuble01,key=lambda x: x[0], reverse=True)
print(tuble03)
res = {k: v for (v, k) in tuble02}
print(res)